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Q. A wire $ABCDEF$ (with each side of length $L$ ) bent as shown in figure and carrying a current $I$ is placed in uniform magnetic field $\vec{B}$ parallel to the positive $y$ direction. The force experienced by the wire in the direction is
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Moving Charges and Magnetism

Solution:

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The magnetic field $\vec{B}=B \hat{j}$. So, the conductors $FE$ and $BA$ are parallel to the magnetic field. These conductors will not experience any force at all. On the other hand, the force on $CB$ is +ve in $x$ -direction and that on $E D$ is in $-$ ve $x$ -direction. So, the forces will cancel each other. The force on the remaining portion $D C$ is $(B I L) \hat{k} .$