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  4. A wheel of mass 15 kg has a moment of inertia of 200 kg-m2 about its own axis, the radius of gyration will be

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Q. A wheel of mass $15 \,kg$ has a moment of inertia of $200 kg-m^{2}$ about its own axis, the radius of gyration will be

System of Particles and Rotational Motion

Solution:

As we know
$I=M k^{2} \Rightarrow \sqrt{\frac{I}{M}}$
$=K=\sqrt{\frac{200}{15}}$
$=\sqrt{\frac{40}{3}}$
$=\sqrt{13.33}=3.65 \,m$