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Q. A wheel completes 2000 revolutions to cover the 9.5 km distance, then the diameter of the wheel is

Jharkhand CECEJharkhand CECE 2010

Solution:

Distance covered in n revolution $ =n2\pi r=n\pi D $
$ \Rightarrow $ $ 2000\pi D=9500 $
[As $ n=2000 $ distance $ =9500\,m $ ]
$ \Rightarrow $ $ D=\frac{9500}{2000\times \pi }=1.5\,m $