Question

A weightless rod is acted upon by upward parallel forces of $2N$ and $4N$ at ends $A$ and $B$ respectively.
The total length of the rod $AB=3m.$ To keep the rod in equilibrium a force of $6N$ should act in the following manner:

• A. downward at any point between $A$ and $B$
• B. downward at the midpoint of $AB$
• C. downward at a point $C$ such that $AC=1m$
• D. downward at a point $D$ such that $BD=1m$

Answer 1

Answer: (D)

for equilibrium net torque at $B$ end $=0$
$-2\left(\right.3\left.\right)+6\times x=0;x=1\,m$