Question

A weight of 290 N and another of 200 N are suspended by a rope on either side of a frictionless pulley. The acceleration of each weight is

• A. 1.5 $ m\text{/}{{s}^{2}} $
• B. 1.8 $ m\text{/}{{s}^{2}} $
• C. 2.2 $ m\text{/}{{s}^{2}} $
• D. 2.5 $ m\text{/}{{s}^{2}} $

Answer 1

Answer: (B)

Acceleration, $ a=\left( \frac{{{m}_{2}}-{{m}_{1}}}{{{m}_{2}}+{{m}_{1}}} \right)g $ $ \Rightarrow $ $ a=\left( \frac{{{W}_{2}}-{{W}_{1}}}{{{W}_{2}}+{{W}_{1}}} \right)g $ $ =\left( \frac{290-200}{290+200} \right)\times 9.8 $ $ \Rightarrow $ $ a=\frac{90\times 9.8}{490} $ $ \Rightarrow $ $ a=1.8\,m\text{/}{{s}^{2}} $