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Q. A weak acid $HA$ has a $K_a$ of $1.00 \times 10^{-5}$. If $0.100$ mole of the acid is dissolved in one litre of water.The percentage of acid dissociated at equilibrium is closest to

AIPMTAIPMT 2007Equilibrium

Solution:

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We know that $Ka = C$ alpha $^{2}$
or $a=\sqrt{\frac{K_{a}}{c}}=\sqrt{\frac{10^{-5}}{10^{-1}}}=10^{-2}=0.001=1$