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Q.
A wave of frequency $500 \,Hz$, travels between $X$ and $Y$, a distance of $600 \,m$ in $2\, s$. How many wavelength are there in distance $X Y$ ?
AMUAMU 2002
Solution:
Wavelength $(\lambda)$ is defined as the distance between repeating units of a wave pattern.
Also, velocity $=\frac{\text { distance }(d)}{\text { time }(t)}$
Given, $d=600 \,m , t=2\, s$
$\therefore v=\frac{600}{2}=300 \,m / s , $
$ f=500\,Hz$
From equation $v=f \lambda$, we have
$\lambda=\frac{v}{f}=\frac{300}{500}=\frac{3}{5} m\,$
Number of waves in $600 \,m =\frac{600}{2 / 5}=1000$.