1. Tardigrade
  2. Question
  3. Physics
  4. A wave moving with constant speed on a uniform string passes the point x=0 with amplitude A0, angular frequency ω0 and average rate of energy transfer P0. As the wave travels down the string it gradually loses energy and at the point x=ℓ, the average rate of energy transfer becomes. At the point x=ℓ, angular frequency and amplitude are respectively:

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Q. A wave moving with constant speed on a uniform string passes the point $x=0$ with amplitude $A_{0}$, angular frequency $\omega_{0}$ and average rate of energy transfer $P_{0}$. As the wave travels down the string it gradually loses energy and at the point $x=\ell$, the average rate of energy transfer becomes. At the point $x=\ell$, angular frequency and amplitude are respectively:

Waves

Solution:

$P=\frac{1}{2} \mu \omega^{2} A^{2} V$ and $v=\sqrt{\frac{T}{\mu}}$ will not change as both $T$ and $\mu$ are constant. $\omega$ will also not change as it is property of the source only that is causing the wave motion. Hence to make power half the amplitude becomes $\frac{A_{0}}{\sqrt{2}}$.