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Q. A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is $v$, the total area around the fountain that gets wet is

AIEEEAIEEE 2011

Solution:

Area $=\pi R_{\max }^{2}$
$R_{\max }=\frac{v^{2} \sin 90^{\circ}}{g}=\frac{v^{2}}{g}$
$\Rightarrow $ Area $=\frac{\pi v^{4}}{g^{2}}$