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  4. A voltmeter of resistance 998 Ω is connected across a cell of emf 2V and internal resistance 2 Ω . The potential difference across the voltmeter is:

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Q. A voltmeter of resistance $ 998\,\Omega $ is connected across a cell of emf 2V and internal resistance $ 2\,\Omega $ . The potential difference across the voltmeter is:

KEAMKEAM 2000

Solution:

From Ohms law $ i=\frac{E}{R+r}=\frac{2}{998+2}=2\times {{10}^{-3}}A $
Potential difference across the voltmeter is $ V=iR=(2\times {{10}^{-3}})\times 998=1.996V $

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