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Q. A Very long magnef of pole strength 4 Am is placed vertically with its one pole on the tabIe .The distance from the pole, the neutral point will be formed is $(B_H=4 \times 10^{-5}T)$

Moving Charges and Magnetism

Solution:

$\frac{\mu_0}{4\pi} \frac{m}{d^2} = B_H$