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  4. A very expensive diamond is polished into a perfect sphere of radius 5 cm. The back surface of the sphere is then covered with silver. If d is the distance of the source of light S from the surface of sphere, then the image coincides with the source. If the index of refraction of diamond is 2.4, then d= ldots × 5 cm.

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Q. A very expensive diamond is polished into a perfect sphere of radius $5 cm$. The back surface of the sphere is then covered with silver. If $d$ is the distance of the source of light $S$ from the surface of sphere, then the image coincides with the source. If the index of refraction of diamond is $2.4$, then $d=\ldots \times 5\, cm$.Physics Question Image

Ray Optics and Optical Instruments

Solution:

Considering refraction at curved surface:
image
$\frac{2.4}{2 \times 5}+\frac{1}{x}=\frac{2.4-1}{5}$
$x=25 \,cm$