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  4. A vertical spring of force constant 100 Nm- 1 is attached to the ceiling, with a block of mass 10 kg suspended from it. Now an external force F is applied on the block so that the spring is stretched by an additional length of 2 m . The work done by the force F is [Take g=10 m s- 2 ] <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-rzxpx6odwfps.png />

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Q. A vertical spring of force constant $100 \, Nm^{- 1}$ is attached to the ceiling, with a block of mass $10 \, kg$ suspended from it. Now an external force $F$ is applied on the block so that the spring is stretched by an additional length of $2 \, m$ . The work done by the force $F$ is [Take $g=10 \, m \, s^{- 2}$ ]



Question

NTA AbhyasNTA Abhyas 2020Work, Energy and Power

Solution:

x = elongation in spring due to mass 10 kg
$= \frac{1 0 \times 1 0}{1 0 0} = \text{1 m}$
$\mathrm{W}_{\mathrm{F}}=\frac{1}{2} \times 100 \times\left[(3)^2-(1)^2\right]-10 \times 10 \times 2$
= $200J$