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Q. A vertical closed cylinder is separated into two parts by a frictionless piston of mass $m$ and of negligible thickness. The piston is free to move along the length of the cylinder. The length of the cylinder above piston is $l_{1},$ and that below the piston is $l_{2},$ such that $l_{1}>l_{2} .$ Each part of the cylinder contains $n$ moles of an ideal gas at equal temperature $T$. If the piston is stationary, its mass $m$ will be given by: (R is universal gas constant and $g$ is the acceleration due to gravity)

NTA AbhyasNTA Abhyas 2020Thermodynamics

Solution:

Solution
$P_{1}+\frac{m g}{A}=P_{2}$
$\Rightarrow \frac{n R T}{l_{1} A}+\frac{m g}{A}=\frac{n R T}{l_{2} A}$
$\Rightarrow m=\frac{n R T}{g}\left(\frac{1}{l_{2}}-\frac{1}{l_{1}}\right)$
$=\frac{n R T}{g}\left(\frac{l_{1}-l_{2}}{l_{1} l_{2}}\right)$