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Q. A vehicle of mass $ m $ is moving on a rough horizontal road with momentum $ p $ . If the coefficient of friction between the tyres and the road be $ \mu $ , then the stopping distance is

Punjab PMETPunjab PMET 2010Laws of Motion

Solution:

Stopping distance
$s=\frac{u^{2}}{2 \,\mu g}=\frac{m^{2}\, u^{2}}{2\, \mu g m^{2}}=\frac{p^{2}}{2 \mu m^{2}\,g}$