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Q. A uniformly charged ring of radius $3a$ and total charge $q$ is placed in xy-plane centred at origin. A point charge $q$ is moving towards the ring along the z-axis and has speed $u$ at $z = 4a$. The minimum value of $u$ such that it crosses the origin is :

JEE MainJEE Main 2019Electrostatic Potential and Capacitance

Solution:

$U_i + K_i = U_f + K_f$
$\frac{kq^{2}}{\sqrt{16a^{2}+9a^{2}}} + \frac{1}{2}mv^{2} = \frac{kq^{2}}{3a} $
$ \frac{1}{2} mv^{2} = \frac{kq^{2} }{a} \left(\frac{1}{3} - \frac{1}{5}\right) = \frac{2kq^{2}}{15a} $
$ v= \sqrt{\frac{4kq^{2}}{15ma}} $