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  4. A uniform wire of resistance 9 Ω is cut into equal parts. They are connected in the form of equilateral triangle ABC. A cell of emf 2 V and negligible internal resistance is connected across B and C. Potential difference across AB is:

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Q. A uniform wire of resistance $ 9\,\Omega $ is cut into equal parts. They are connected in the form of equilateral triangle ABC. A cell of emf 2 V and negligible internal resistance is connected across B and C. Potential difference across AB is:

KEAMKEAM 2001

Solution:

$ R=\frac{9}{3}=3\,\Omega $
$ {{R}_{net}}=2\,\Omega $
PD across AB
$ V=i\times R=\frac{V}{{{R}_{net}}}\times R $
$ =\frac{2}{2}\times 3=3V $

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