1. Tardigrade
  2. Question
  3. Physics
  4. A uniform rope of mass M and length L is fixed at its upper end vertically from a rigid support. Then the tension. in the rope at the distance I from the rigid support is x

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A uniform rope of mass $M$ and length $L$ is fixed at its upper end vertically from a rigid support. Then the tension. in the rope at the distance $I$ from the rigid support is $x$

Laws of Motion

Solution:

For the lower part
image
Mass of the lower part is $m'$
$m'=$ Mass per unit length $\times$ length of lower part
$=\frac{M}{L}(L-I)$
So, Using $\vec{F_{\text {net }}}=m \vec{a}$
here $\vec{a}=0$
$T-\frac{M}{L}(L-I) g=0$
$T=\frac{M}{L}(L-I) g$