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Q. A uniform rod of mass $'m'$ and length $'l'$ lying on a smooth horizontal table is pivoted about one end. An impulse $'J'$ is applied to the other end. Angular speed with which rod starts rotating is

NTA AbhyasNTA Abhyas 2020

Solution:

Angular impulse $=I\left(w_{2} - w_{1}\right)$
$\Rightarrow J\times l=\frac{m l^{2}}{3}\left(w - 0\right)\Rightarrow w=\frac{3 J}{m l}$