Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A uniform metre scale balances at the $40\, cm$ mark when weights of $10\, g$ and $20\, g$ are suspended from the $10-cm$ and $20-cm$ marks respectively. The weight of the metre scale is

Solution:

$10 g \times 30+20 g \times 20=W \times 10$