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Q. A uniform disc of radius R put over another uniform disc of radius 2R of same thickness and density, the peripheries of the two discs touch each other. The position of their centre of mass is

Solution:

Distance of C.M. from centre of big disc
$x = \frac{r^2 a}{R^2 +r^2}$
r- radius of small disc
R- radius of big disc
a- distance between the centres of discs