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Q. A uniform cylinder of mass $M$ and radius $R$ is to be pulled over a step of height a $(a < R)$ by applying a force $F$ at its centre $'O'$ perpendicular to the plane through the axes of the cylinder on the edge of the step (see figure). The minimum value of $F$ required is :

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JEE MainJEE Main 2020System of Particles and Rotational Motion

Solution:

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$(\tau)_{ P }=0$
F.R. $- mgx =0$
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$x=\sqrt{R^{2}-(R-a)^{2}}$
$F = mg \frac{ X }{ R }$
$F =mg \sqrt{1-\left(\frac{ R - a }{ R }\right)^{2}}$
$=$ minimum value of force to pull