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Q. A uniform cylinder has a radius $R$ and length $L$. If the moment of inertia of this cylinder about an axis passing through its centre and normal to its circular face is equal to the moment of inertia of the same cylinder about an axis passing through its centre and normal to its length; then:

System of Particles and Rotational Motion

Solution:

Given $I_{1}=I_{2}$
$\Rightarrow \frac{1}{2} M R^{2}=\frac{m L^{2}}{12}+\frac{m R^{2}}{4}$
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solve to get $L=\sqrt{3} R$