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Q. A uniform conducting wire of length length $10a$ and resistance $R$ is wound up into four turn as a current carrying coil in the shape of equilateral triangle of side $a$. If current $I$ is flowing through the coil then the magnetic moment of the coil is
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Moving Charges and Magnetism

Solution:

Magnetic moment $M=NIA$
$=4\times I\times a^{2} \frac{\sqrt{3}}{4}$
$=\sqrt{3}a^{2}\,I$