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Q. A uniform chain of length $2 \,m$ is kept on a table such that a length of $60 \,cm$ hanges freely from the edge of the table. The total mass of the chain is $4 \,kg$. The work done in pulling the entire chain on the table (Take $g = 10 \,ms^{-2}$)

Work, Energy and Power

Solution:

Mass of length $2 \,m$ of the chain $= 4\, kg$
Mass of length $60\, cm$ or $0.60\, m$ of the chain
$ = \frac{4 \times 0.60}{2} = 1.2\,kg$
Weight of the hanging part of the chain
$= 1.2 \times 10 = 12 \,N$
Since the centre of gravity of the hanging part lies at its mid point, i.e. $30\, cm$ or $0.30 \,m$
$\therefore W = 12 \times 0.30 = 3.6\,J$