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Physics
A two metre wire is moving with a velocity of 1 m / s perpendicular to a magnetic field of 0.5 Wb / m 2. The e.m.f. induced in it will be
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Q. A two metre wire is moving with a velocity of $1\, m / s$ perpendicular to a magnetic field of $0.5\, Wb / m ^{2}$. The e.m.f. induced in it will be
Electromagnetic Induction
A
0.5 volt
26%
B
0.1 volt
10%
C
1 volt
56%
D
2 volt
8%
Solution:
$e=B v l=0.5 \times 2 \times 1=1\, V$