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  4. A two-fold increase in intensity of a wave implies an increase of (Given: log10 2 = 0.3010.)

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Q. A two-fold increase in intensity of a wave implies an increase of (Given : $log_{10} 2 = 0.3010$.)

Waves

Solution:

$L=10 \log _{10} \frac{I}{I_{0}}$ decibel
$L,=10 \log _{10} \frac{2 I}{I_{0}}$ decibel
$L'-L =10\left[\log _{10} \frac{2 I}{I_{0}} \log _{10} \frac{I}{I_{0}}\right]$
$=10 \log _{10} 2=10 \times 0.3010=3.01 dB$