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Q. A TV tower has a height $160 \,m$. Its coverage range is nearly (Earth's radius, $R_{e}=6400 \,km$ )

AP EAMCETAP EAMCET 2019

Solution:

Given, height of a TV tower, $h=160 \,m$
Radius of earth, $R=6400\,km =6.4 \times 10^{6} \,m$
Coverage range of TV tower is given by
$d=\sqrt{2 R h}=\sqrt{2 \times 6.4 \times 10^{6} \times 160}=45254.8=45255 \,m$