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Q. A tuning fork vibrates with frequency $256\, Hz$ and gives one beat per second with the third normal mode of vibration of an open pipe. What is the length of the pipe ? (Speed of sound in air is $340\, ms^{-1}$)

JEE MainJEE Main 2018Waves

Solution:

Given: Frequency of tuning fork $=256 Hz$.
It gives one beat per second with the third normal mode of vibration of an open pipe.
Therefore, frequency of open pipe $=(256+1) Hz$
Speed of sound in air is $340 m / s$.
Now we know, frequency of third normal mode of vibration of an open pipe is given as
$f=\frac{3 v_{\text {sound }}}{2 l}$
$\Rightarrow \frac{3 \times 340}{2 l}=255$
$\Rightarrow l=\frac{3 \times 340}{2 \times 255}=2\, m =200\, cm$