1. Tardigrade
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  3. Physics
  4. A tuning fork A of frequency 512 Hz produces 5 beats per second when sounded with another tuning fork B of unknown frequency. If B is loaded with wax the number of beats is again 5 per second. The frequency of the tuning fork B before it was loaded is

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Q. $A$ tuning fork $A$ of frequency $512\, Hz$ produces $5$ beats per second when sounded with another tuning fork $B$ of unknown frequency. If $B$ is loaded with wax the number of beats is again $5$ per second. The frequency of the tuning fork $B$ before it was loaded is

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Solution:

Frequency of $A , n =512 \,Hz$
Number of beats $/ sec , m =5$
$\therefore $ Frequency of $B , n '=512 \pm 5=517$ or $505$
On loading $B$, its frequency decreases from $517$ to $505$ ,
so that number of beats per second remains $5$ .
Hence, frequency of $B$, when not loaded $=517 \,Hz$