1. Tardigrade
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  4. A tuning fork A of frequency 512 Hz produces 5 beats per second when sounded with another tuning fork B of unknown frequency. If B is loaded with wax, the number of beats is again 5 per second. The frequency of tuning fork B before it was loaded is

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Q. A tuning fork $A$ of frequency $512\, Hz$ produces $5$ beats per second when sounded with another tuning fork $B$ of unknown frequency. If $B$ is loaded with wax, the number of beats is again $5$ per second. The frequency of tuning fork $B$ before it was loaded is

Solution:

$f_{A} \sim f_{B}=5$
On loading $f_{B}$ decreases and again beats produced are $5$ per second.
Hence in later case $f_{A} \sim f_{B}=5$ originally
$f_{B}-f_{A}=5$
$F_{B}=5+512=517 \,Hz$