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Q. A truck of mass $0.5$ Ton is moving with a speed of $6\, ms ^{-1}$. Sand is poured at the rate of $10\, Kg$ per minute. How much force is needed to keep it moving with the same speed?

KCETKCET 2022

Solution:

$F=\frac{d(m v)}{d t}=v \frac{d m}{d t}=6 X \frac{10}{60}=1\, N$