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Q. A trolley is moving horizontally with a constant velocity of $v( m / s )$ w.r.t. the earth. A man starts running from one end of the trolley with a velocity $1.5\, v( m / s )$ w.r.t. to trolley. After reaching the opposite end, the man returns to starting end and continues running with a velocity of $1.5 \,v( m / s )$ w.r.t. the trolley in the backward direction. If the length of the trolley is $L$, then the displacement of the man with respect to the earth during the process is $\frac{p L}{q}$. Find $(p+q)$Physics Question Image

Motion in a Straight Line

Solution:

Time taken by the man to return to its starting point on trolley is
$t=\frac{2 L}{1.5 v}$
Displacement of the man w.r.t. the earth during this process is
$S=v \times t=v \times \frac{2 L}{1.5 v}=\frac{4 L}{3} m$