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Q. A triode has a plate resistance of $10\, k \Omega$ and amplification factor $24$. If the input signal voltage is $0.4\, V$ (r.m.s.), and the load resistance is $10\, k \Omega$, then, the output voltage (r.m.s.) is

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Use $V_{0}=A V_{s}$
Now $A=\frac{24 \times 10 k}{10 k+10 k}=\frac{24 \times 10}{20}=12$
Therefore, $V_{0}=12 \times 0.4$ volt(r.m.s) $=4.8 \,V$