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Q. A triatomic, diatomic and monatomic gas is supplied same amount of heat at constant pressure, then

Thermodynamics

Solution:

$\frac{\Delta U}{\Delta Q}=\frac{n C_{V} \Delta T}{n C_{P} \Delta T}=\frac{C_{V}}{C_{P}}=\frac{1}{\gamma}$
$\left(\frac{\Delta U}{\Delta Q}\right)_{\text {mono }}=\frac{1}{\gamma_{\text {mono }}}=\frac{3}{5}$
$\left(\frac{\Delta U}{\Delta Q}\right)_{\text {dia }}=\frac{1}{\gamma_{\text {dia }}}=\frac{5}{7}$
$\left(\frac{\Delta U}{\Delta Q}\right)_{\text {tria }}=\frac{1}{\gamma_{\text {tria }}}=\frac{3}{4}$
Fractional energy used to change internal energy is maximum in Triatomic gas.