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Q. A transition element X has the configuration $ [Ar]{{d}^{4}} $ in its $ +\,3 $ oxidation state. Its atomic number is

Jharkhand CECEJharkhand CECE 2010

Solution:

Given, $ X=[Ar]{{d}^{4}} $ $ \therefore $ The complete configuration of the ion, $ {{X}^{3+}}=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}}3{{p}^{6}},3{{d}^{4}} $ $ \therefore $ $ X=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},3{{d}^{5}}4{{s}^{2}} $ $ \therefore $ The atomic number of the element is 25 and the element is Mn.