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Physics
A transformer with efficiency 80% works at 4 kW and 100 V. If the secondary voltage is 200 V, then the primary and secondary currents are respectively
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Q. A transformer with efficiency 80% works at $4\, kW$ and $100\, V$. If the secondary voltage is $200\,V$, then the primary and secondary currents are respectively
AIIMS
AIIMS 2017
Alternating Current
A
40 A and 16 A
67%
B
16 A and 40 A
12%
C
20 A and 40 A
9%
D
40 A and 20 A
12%
Solution:
Here, $\eta$ = 80 %
$P_{i} $ = 4 kW = 4000 W
$V_{p}$ = 100 V, Vs = 200 V
$I_{p}=\frac{p_{i}}{V_{p}}=\frac{4000}{100}=40\,A$
$\eta=\frac{V_{s}\,I_{s}}{V_{p}\,I_{p}};\, \frac{80}{100}=\frac{200I_{s}}{4000}=\frac{I_{s}}{20}$
or $I_{s}=\frac{20\times80}{100}=16\,A$