Question

A train with cross-sectional area $S_{t}$ is moving with speed $v_{t}$ inside a long tunnel of cross-sectional area $S_{0}\left(S_{0}=4 S_{t}\right)$. Assume that almost all the air (density $\rho$ ) in front of the train flows back between its sides and the walls of the tunnel. Also, the air flow with respect to the train is steady and laminar. Take the ambient pressure and that inside the train to be $p_{0}$. If the pressure in the region between the sides of the train and the tunnel walls is $p$, then $p_{0}-p=\frac{7}{2 N} \rho v_{t}^{2}$. The value of $N$ is________.

Answer 1

The velocity of air flow relative to the train between its sides and the walls of the tunnel is $v$
$v \times 3 S _{ t }= v _{ t } 4 S _{ t }$
$v=\frac{4}{3} v_{t}$ ...... (i)
Now,
$P+\frac{1}{2} \rho v^{2}=P_{0}+\frac{1}{2} \rho v_{t}^{2} $
$P_{0}-P=\frac{1}{2} \rho\left(v^{2}-v_{t}^{2}\right)$
$=\frac{1}{2} \rho v_{t}^{2}\left(\frac{16}{9}-1\right) $
$P_{0}-P=\frac{7}{18} \rho v_{t}^{2} $
Hence $N=9$