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Q. A train is moving east at a speed of $5\, ms ^{-1}$. A bullet fired westwards with a velocity of $10\, ms ^{-1}$ crosses the train in $8\, s$. The length of the train is

Motion in a Straight Line

Solution:

Take west as positive, then
$v_{B T}=v_{B}-v_{T}=10-(-5)=15 \frac{ m }{ s }$
$s_{B T}=v_{B T}. t=\left(15 \frac{ m }{ s }\right) \cdot(8 s )=120\, m$