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  4. A toy cyclist completes one round of a square track of side 2 m in 40s . What will be the displacement at the end of 3 min?

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Q. A toy cyclist completes one round of a square track of side $ 2 $ m in $ 40s $ . What will be the displacement at the end of $ 3 $ min?

KEAMKEAM 2006

Solution:

Displacement is distance from initial to final position.
In $ 40\,s-1 $ round In $ 3\times 60=180\text s - 4\frac{1}{2} $ round Displacement for 4 rounds is zero.
For $ \frac{l}{2} $ round, length of diagonal $ =2\sqrt{2}m $ .

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