Tardigrade
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Tardigrade
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Physics
A thin wire of mass m and length l is bent to form a semicircle. The gravitational potential at the centre of the semicircle is
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Q. A thin wire of mass $m$ and length $l$ is bent to form a semicircle. The gravitational potential at the centre of the semicircle is
Gravitation
A
$-\frac{\pi G m}{l}$
22%
B
$-\frac{2 \pi G m}{l}$
23%
C
$\frac{-3 \pi G m}{l}$
9%
D
zero
45%
Solution:
At the centre,
$V=-\frac{G m}{r}$ but $\pi r=l$
$\Rightarrow V=-\frac{\pi G m}{l}$