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  4. A thin wire carries a uniformly distributed charge Q=3.14nC along its length. The wire is bent in the form of a semi-circular arc of radius R=1m (without disturbing the charge distribution). Find the electric field at the center of curvature of the arc (in N/C ).

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Q. A thin wire carries a uniformly distributed charge $Q=3.14nC$ along its length. The wire is bent in the form of a semi-circular arc of radius $R=1m$ (without disturbing the charge distribution). Find the electric field at the center of curvature of the $arc$ (in $N/C$ ).

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$E=\frac{2 k \lambda }{R}\sin\frac{\theta }{2}=\frac{2 k Q}{\pi R^{2}}\sin\frac{\pi }{2}$