1. Tardigrade
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  4. A thin uniform rod A B of mass m=1 kg moves translationally with acceleration a=2 m / s 2 due to two antiparallel forces F1 and F2. The distance between the points at which these forces are applied is equal to l=20 cm. Besides, it is known that F2=5 N. The length of the rod is .

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Q. A thin uniform rod $A B$ of mass $m=1 \,kg$ moves translationally with acceleration $a=2 \,m / s ^{2}$ due to two antiparallel forces $F_{1}$ and $F_{2}$. The distance between the points at which these forces are applied is equal to $l=20\, cm$. Besides, it is known that $F_{2}=5 \,N$. The length of the rod is ____.Physics Question Image

System of Particles and Rotational Motion

Solution:

Let $x$ be the distance of centre point of rod from $D$.
Then, $F_{2}-F_{1}=m a$
or $F_{1}=3 N$
Further, $\tau_{c}=0$
$\therefore F_{2} x=F_{1}(0.2+x) $
$ 5 x=F_{1}(0.2+x)$
$\therefore 5 x=3(0.2+x) $
or $ x=0.3\, m$
$\therefore$ Length of rod $=2(x+0.2)=1.0 \,m$

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