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  4. A thin uniform circular ring is rolling down an inclined plane of induction 30° without slipping, its linear acceleration along the inclined plane will be

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Q. A thin uniform circular ring is rolling down an inclined plane of induction 30$^\circ$ without slipping, its linear acceleration along the inclined plane will be

System of Particles and Rotational Motion

Solution:

$a = \frac{g \, sin \theta}{1 + \frac{k^2}{R^2}} = \frac{g \, sin \, 30^\circ}{1 + 1} = \frac{g}{2} \times \frac{1}{2} = \frac{g}{4}$