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Q. A thin spherical conducting shell of radius $R$ has a charge $q$. Another charge $Q$ is placed at the centre of the shell. The electrostatic potential at a point $p$ a distance $\frac{R}{2}$ from the centre of the shell is

Electrostatic Potential and Capacitance

Solution:

Electric potential at $P$,
image
$V=\frac{k \cdot Q}{R / 2} +\frac{k \cdot q}{R}$
$=\frac{2 Q}{4 \pi \varepsilon_{0} R}+\frac{q}{4 \pi \varepsilon_{0} R}$