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  4. A thin sheet of glass (μ=1.5) of thickness 6 micron introduced in the path of one of the interfering beams in a double slit experiment shifts the central fringe to a position previously occupied by fifth bright fringe. Then the wavelength of light used is

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Q. A thin sheet of glass $(\mu=1.5)$ of thickness $6$ micron introduced in the path of one of the interfering beams in a double slit experiment shifts the central fringe to a position previously occupied by fifth bright fringe. Then the wavelength of light used is

BITSATBITSAT 2020

Solution:

$n \lambda=(\mu-1) t$
$\therefore \lambda=\frac{(\mu-1) t}{n}$
$=\frac{(1.5-1) \times 6 \times 10^{-6}}{5}=6000 \,\mathring{A}$