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Q. A thin metal disc of radius r floats on water surface and bends the surface downwards along the perimeter making an angle $ \theta $ with verticle edge of the disc. If the disc displaces a weight of water W and surface tension of water is T, then the weight of metal disc is

AMUAMU 1999

Solution:

: Weight of disc = upthrust $ + $ force due to T $ =W=2\pi rT\cos \theta $ $ =2\pi rT\cos \theta +W $