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Q. A thin convex lens of crown glass having refractive index 1.5 has power 1 D. What will be the power of similar convex lens of refractive index 1.6 ?

Ray Optics and Optical Instruments

Solution:

$P=\frac{1}{f}(n-1)\left(\frac{1}{R_1}-\frac{1}{R_2}\right)$
$Hence \,\frac{P_2}{P_1}=\frac{(n_2-1)}{(n_1-1)}That\,is \frac{p_2}{1}=\frac{1.6-1}{1.5-1}$
$Hence\,p_2=1.2$