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Q. A thin circular ring of mass $M $and radius $r $ is rotating about its axis with a constant angular velocity $\omega$. Four objects each of mass $m$, are kept gently to the opposite ends of two perpendicular diameters of the ring. The angular velocity of the ring will be

AIPMTAIPMT 2003System of Particles and Rotational Motion

Solution:

According to conservation of angular momentum,
$L=I \omega=$ constant.
Therefore, $I_{2} \omega_{2}=I_{1} \omega_{1}$
or $\omega_{2}=\frac{I_{1} \omega_{1}}{I_{2}}=\frac{M k^{2} \omega}{(M+4 m) k^{2}}=\frac{M \omega}{M+4 m}$.