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  4. A thin bar magnet of length 2L is bent at the mid-point so that the angle between them is 60° . The new length of the magnet is:

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Q. A thin bar magnet of length $2L$ is bent at the mid-point so that the angle between them is $ 60{}^\circ $ . The new length of the magnet is:

ManipalManipal 2008Magnetism and Matter

Solution:

On bending the magnet, the length of the magnet
$ AC=AB+BC $
$ =L\sin \left( \frac{\theta }{2} \right)+L\sin \left( \frac{\theta }{2} \right) $
$ =L\sin \left( \frac{\theta }{2} \right) $
$ =2L\sin 30{}^\circ $
$ =2L\times \frac{1}{2}=L $